Java: an ordered index with TreeMap
Use a sorted map the way a database uses an ordered index to answer range and nearest-key queries.
On this page
Java Map basics.
- Use a sorted map the way a database uses an ordered index to answer range and nearest-key queries.
- Predict the sample output and explain the state changes.
- Complete the practice task and check the boundary cases.
The concept
A database index maps a column value to the rows that hold it. A hash index answers exact lookups quickly but cannot answer range queries such as ages between 25 and 40. An ordered index, usually a B-tree, keeps keys sorted and supports both.
TreeMap is a sorted map built on a balanced tree, so it keeps its keys in order and each operation takes O(log n). firstKey and lastKey give the minimum and maximum, subMap returns a range, and floorKey and ceilingKey find the nearest keys below and above a value. TreeMap itself is an in-memory tree, not a B-tree, but it behaves like an ordered index.
Code example
import java.util.*;
class Main {
public static void main(String[] args) {
TreeMap<Integer, String> byAge = new TreeMap<>();
byAge.put(31, "Cy");
byAge.put(24, "Ada");
byAge.put(45, "Di");
byAge.put(29, "Bo");
System.out.println(byAge.firstKey() + " " + byAge.lastKey());
System.out.println(byAge.subMap(25, true, 40, true));
System.out.println(byAge.floorKey(30) + " " + byAge.ceilingKey(30));
}
}24 45
{29=Bo, 31=Cy}
29 31Follow the code
Open the walkthrough to inspect the example one step at a time.
Show guided walkthrough
import java.util.*; class Main { public static void main(String[] args) { TreeMap<Integer, String> byAge = new TreeMap<>(); byAge.put(31, "Cy"); byAge.put(24, "Ada"); byAge.put(45, "Di"); byAge.put(29, "Bo"); System.out.println(byAge.firstKey() + " " + byAge.lastKey()); System.out.println(byAge.subMap(25, true, 40, true)); System.out.println(byAge.floorKey(30) + " " + byAge.ceilingKey(30)); }}Follow the example
Start to inspect the source, values, and output. These prepared steps explain the published sample; grouped loop steps describe multiple iterations.
View the complete dry-run table
| Step / line | What happens | State after step | Output so far |
|---|---|---|---|
| The four keys are kept in sorted order: 24, 29, 31, 45. | keys = 24, 29, 31, 45 | — | |
| The smallest and largest keys are at the ends of the tree. | keys = 24, 29, 31, 45 | 24 45 | |
| A range query: ages from 25 through 40. | keys = 24, 29, 31, 45 | 24 45
{29=Bo, 31=Cy} | |
| The nearest key at or below 30 is 29; the nearest at or above is 31. | keys = 24, 29, 31, 45 | 24 45
{29=Bo, 31=Cy}
29 31 |
Behind the scenes
How Java processes this code
The Java compiler produces bytecode. The JVM loads the class and invokes its main method.
Cost and common mistakes
put, get, floorKey, and ceilingKey are O(log n); a range query costs O(log n + k) for k results.
- TreeMap needs keys that are comparable. Mixing incomparable types throws ClassCastException.
- A TreeMap holds one value per key. A non-unique index must map each key to a list of rows.
Try it yourself
Which keys does byAge.headMap(30) contain?
Reveal answer and reasoning
It holds the keys strictly below 30: {24=Ada, 29=Bo}.